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<img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/CEN_CAL_C10_S01_056_S01.png" width="80%"> <br> Let at time t the depth of water is h and radius of water surface is r. If in time dt the decrease of water level is dh, then <br> `-pir^(2)dh=aksqrt(2gh)dt` <br> or `(-pir^(2))/(aksqrt(2h)sqrt(h))=dt` <br> or `(-pir^(2))/(aksqrt(2g))=(dh)/sqrt(h)=dt` <br> Now when t=0, h=H and when t=t, h=0, then <br> `-(pir^(2))/(aksqrt(2g))int_(H)^(0)(dh)/sqrt(h) = int_(0)^(t)dt` <br> or `(-pir^(2))/(aksqrt(2g)){2sqrt(h)}_(H)^(0)=t` <br> or `t=(pir^(2)2sqrtH)/(aksqrt(2g)) = (pir^(2))/(ak) sqrt((2H)/(g))`**What is differential equation and order and degree of a differential equation**

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